[timotheus m]

Ok, I see what you mean.
I changed it to a different handler now..but still it doesnt work. When triggering interrupt 1 it even restarts and prints:
Start
Loop

// **** INCLUDES *****
#include "LowPower.h"

const int int_trigger_A = 2; // pd2 int0
const int wakeUpPin = 3;     // pd3 int1

volatile boolean HANDLER_wakeUp = false;
volatile boolean HANDLER_int_trigger = false;
volatile int sleepmode = 1;
long count;

void wakeUp()
{
  HANDLER_wakeUp = true;
}

void int_trigger()
{
  HANDLER_int_trigger = true;
}

void setup()
{
  pinMode(wakeUpPin, INPUT_PULLUP);
  pinMode(int_trigger_A, INPUT_PULLUP);
  Serial.begin(9600);
  Serial.println("Start");
  delay(100);
}

void loop()
{
  Serial.println("Loop");
  delay(500);

  attachInterrupt(0, int_trigger_A, FALLING);
  attachInterrupt(1, wakeUp, FALLING);// Wake up when wake up pin is low.
  if (sleepmode == 1) {  delay(100); LowPower.powerDown(SLEEP_FOREVER, ADC_OFF, BOD_OFF); }
  if (sleepmode == 2) {  delay(100);  LowPower.powerDown(SLEEP_1S, ADC_OFF, BOD_OFF); }
  detachInterrupt(1); // Disable external pin interrupt on wake up pin.
  detachInterrupt(0);
  
  // Do something here
  // Example: Read sensor, data logging, data transmission.
  
  delay(100);

  if (HANDLER_int_trigger) {
    HANDLER_int_trigger = false;
    sleepmode = 1;
    Serial.println("int_trigger");
    delay(500);
  }

  if (HANDLER_wakeUp) {
    HANDLER_wakeUp = false;
    sleepmode = 1;
    Serial.println("wakeUp");
    delay(500);
  }

  if (digitalRead(int_trigger_A==LOW)) {
    sleepmode = 2;
    count++;
    Serial.println("count++");
  }
  else {
  Serial.println(count);
  delay(500);
  sleepmode = 1;
  }
  
  

}

[timotheus m]

HI,
appreciate your reply. What do you mean there’s only a fraction of time?
I used the example where it’s done as far as I can see the exact same way besides that I’m using two interrupts.
What would you change to get it running?

[Author]

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